Practicing Success

Target Exam

NEET

Subject

Physics

Chapter

Oscillations and Waves

Question:

In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be: 

Options:

536 Hz

537 hz

523 Hz

524 Hz

Correct Answer:

524 Hz

Explanation:

Difference of fA and fB is 6 Hz

If tension decreases, fB decreases and becomes f'B .

Now, difference of fA and f'B = 7 Hz (increases)

So, fA > fB fA – fB = 6 Hz

fA = 530 Hz ; fB = 524 Hz (original)